x/x+2-x+20/x^2-4=x/x-2

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Solution for x/x+2-x+20/x^2-4=x/x-2 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

20/(x^2)-x+x/x-4+2 = x/x-2 // - x/x-2

20/(x^2)-x+x/x-(x/x)-4+2+2 = 0

20/(x^2)-x+x/x-4-1+2+2 = 0

20*x^-2-x = 0

x*(20*x^-3-1) = 0

20*x^-3 = 1 // : 20

x^-3 = 1/20

-3 < 0

1/(x^3) = 1/20 // * x^3

1 = 1/20*x^3 // : 1/20

20 = x^3

x^3 = 20 // ^ 1/3

x = 20^(1/3)

x = 0

x = 0

x in { 0} 

x = 20^(1/3)

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